Question
In ∆ABC , G is the centroid , AB = 20 cm, BC= 24 cm
and AC = 28 cm , find GD, where D is the mid-point of BC?Solution
If AD is the median, then we know, AB² + AC² = 2{AD² + (BC/2)²} or 202 + 282 = 2{AD 2 + (24/2) 2 } or 400 + 784 = 2{AD 2 + 144} or 1184/2 = AD 2 + 144 or 592 = AD 2 + 144 or AD 2 = 592 – 144 = 448 or AD = √448 = 8√7 Now G divides median in 2:1 so GD = 1/3 of AD = 1/3 of 8√7 = 8√7 /3cm
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