Question
If G is the centroid and AD, BE, CF are three medians of
∆AGF with area 11 cm 2 , then the area of ∆ABC is?Solution
Meeting point of all medians AD, BE , CF is called as centroid. Always remember that, if G is centroid in ∆ ABC, In ∆ ABC, area of ∆ AGF = area of ∆ AGE = area of ∆ BGD = area of ∆BGF = area of ∆CGE = area of ∆CGD = 1/6th of the area of ∆ABC So area of ∆AGF = 1/6 th of area of ∆ABC 11 = 1/6 × area of ∆ABC = 66 cm 2
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...