Question
If median AD of an equilateral ∆ABC is 6 cm and G is
centroid. Find AG?Solution
Meeting point of all medians is called as centroid. Always remember that centroid divided median in 2:1 So here AG: GD = 2:1 & AD = 6 cm So dividing 6 into 2:1 , AG = 2/3 of AD = 2/3 of 6 = 4 cm
‘a’ is directly proportional to ‘b’. If at a=30, the value of ‘b’ is 20% greater than ‘a’, then find the value of ‘a’ when b=54.
...If a + `1/b` = 1 and b + `1/c` =1 , then the value of c + `1/a` is
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
√(92×8 ×52+700) = ?
If x4 + x - 4 = 47 then find the value of (x + x-1).
If a + b + c = 5, a³ + b³ + c³ = 85 and abc =25, then find the value of a² + b² + c² – ab –bc – ca
- If x + 4y = 26 and 4x + y = 41, then find the value of (x - y).
- If p = 25 - q - r and pq + r(p + q) = 256, then find the value of (p² + q² + r²).
If 10x2 – 6xy+y² – 4x+4= 0, then find the value of (3x+2y).
Find the value of ‘x’ in the given expression:
(49/16)x × (64/343)x-1 = 4/7
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