Question
From an external point P, two tangents PR and PS are
drawn to a circle with a radius of 10 cm. If the length of each tangent is 14 cm, determine the perimeter of quadrilateral ORPS, where O is the center of the circle.Solution
We know that the length of tangents drawn from an external point to the circle is equal. i.e. RP = PS = 14 cm
Required perimeter = OR + RP + PS + OS = 10 + 14 + 14 + 10 = 48 cm
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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