Question
ABCD is a parallelogram such that DM is perpendicular to
side AB and length of AM is 6 cm while length of MB is 20 cm. If length of AD is 10 cm, then find the area of the parallelogram.Solution
In right triangle DMA; Length of DM = (102 – 62)1/2 = (100 – 36)1/2 = 8 cm So, length of base of the parallelogram = 6 + 20 = 26 cm So, area of the parallelogram = base × height = 26 × 8 = 208 cm2
More Geometry Questions
124.80 + 50.01 + √170 = ? ÷ 5
? % of 759.96 + 932.99 = 1237.01
(359.92÷24.02)+(230.04÷5)=?% of 210.0-86.1
? + 165.99 – 104.01 = 26.01 × 7.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(2160.23 ÷ 35.98) + (600.32 ÷ 23.9) + 1744.11 = ?
?% of (144.31 ÷ 17.97 × 60.011) = 239.98
(129.98% of 8460) + (119.899% of 8640) = (130.009% of 15820) + ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
15.03% of (619.87 × 7) + (√399.63 × 16.11) ÷ 5 = ?
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