Question
ABCD is a parallelogram such that DM is perpendicular to
side AB and length of AM is 6 cm while length of MB is 20 cm. If length of AD is 10 cm, then find the area of the parallelogram.Solution
In right triangle DMA; Length of DM = (102 – 62)1/2 = (100 – 36)1/2 = 8 cm So, length of base of the parallelogram = 6 + 20 = 26 cm So, area of the parallelogram = base × height = 26 × 8 = 208 cm2
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