Question
ABC is an isosceles triangle where AB = AC which is
circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?Solution
we know that PA = PB 
here is Given that AB = AC if AL = x and LB = K then AB = x + K then AC will be = x + K if AL = x, LB = K then BP = K [ ∵ AL = AM] So AM = x, So MC = k as we Know AB = AC If MC = k then PC = K and LB = K then BP = K Means PC = BP
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