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      Question

      ABC is an isosceles triangle where AB = AC which is

      circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?
      A BP = PC Correct Answer Incorrect Answer
      B BP > PC Correct Answer Incorrect Answer
      C BP < PC Correct Answer Incorrect Answer
      D BP = 1/2PC Correct Answer Incorrect Answer

      Solution

      we know that PA = PB here is Given that AB = AC if AL = x and LB = K then AB = x + K then AC will be = x + K if AL = x, LB = K then BP = K [ ∵ AL = AM] So AM = x, So MC = k as we Know AB = AC If MC = k then PC = K and LB = K then BP = K Means PC = BP

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