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In the given figure ∠ABF + ∠CBF = 180˚ (Angles in a straight line) 75˚ + ∠CBF = 180˚ ∠CBF = 105˚ Now, in ∆CBE ∠CBE + ∠BCE + ∠CEB = 180˚ 105˚ + ∠BCE + 44˚ = 180˚ ∠BCE = 180˚ - (105˚+ 44˚) ∠BCE = 31˚ ∠BCE + ∠DFB = 180˚ (Sum of opposite sides of Cyclic Quadrilateral) ∠DFB = 180˚ - 31˚ = 149˚ ∠DFB + ∠AFB = 180˚ ∠AFB = 180˚ - 149˚ = 31˚ In ∆ABF ∠AFB + ∠FAB + ∠AFB = 180˚ ∠FAB = 180˚-(75˚+31˚) = 74˚
If x 2 – 15x + 51 = 0, then determine the value of (x – 5) + {1/(x – 5)}.
√(92×8 ×52+700) = ?
{(21/20) + (20/21)}2 - {(21/20) - (20/21)}2 = ?
In a college, the proportion of boys to girls is 7:9, and the proportion of graduate students to postgraduate students is 4:5. Determine the total numbe...
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
If a3 + b3 = 6240 and a + b = 30, then find the value of {(a + b)2 – 3ab}
If 15a2 + 1 = 20a, then find the value of {(9a2 + 1)/25a2}
1/3 + 1/15 + 1/35 + 1/63 + 1/99 = ?
In a class of 70 students and 25 teachers, each student got gifts that were 20% of total number of students and each teacher got gifts that were 10% of ...
