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In the given figure ∠ABF + ∠CBF = 180˚ (Angles in a straight line) 75˚ + ∠CBF = 180˚ ∠CBF = 105˚ Now, in ∆CBE ∠CBE + ∠BCE + ∠CEB = 180˚ 105˚ + ∠BCE + 44˚ = 180˚ ∠BCE = 180˚ - (105˚+ 44˚) ∠BCE = 31˚ ∠BCE + ∠DFB = 180˚ (Sum of opposite sides of Cyclic Quadrilateral) ∠DFB = 180˚ - 31˚ = 149˚ ∠DFB + ∠AFB = 180˚ ∠AFB = 180˚ - 149˚ = 31˚ In ∆ABF ∠AFB + ∠FAB + ∠AFB = 180˚ ∠FAB = 180˚-(75˚+31˚) = 74˚
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