Question
The value of x which satisfies the equation
(x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) / (a+b) = 0 isSolution
For this Question put a = 2, b = 1, c = 1 As we Know Here is only one equation and four variable a, b, c & x, so we can put a, b, c anything else we put a = 2, b = 1, c = 1 On putting ((x+4+2 ) / 2) + ((x+1+8) / 3) + ((x+1+2) / 3) = 0 ⇒ ((6+x)/2) + ((9+x)/3) + ((3+x)/3) = 0 ⇒ 18+3x +18+2x+6 + 2x = 0 ⇒ 7x + 42 = 0, x = - 6 ⇒ putting in option a = 2, b = 1, c = 1 we get option (2) satisfy So = -(a²+b²+c²) = - (4+1+1) ⇒ - 6
14, 17, 23, 32, ?, 59
32, 64, 8, ?, 2, 4Â
9 19 39 ? 159 319
18   29   16   31   ?   33
13, 29, 65, 129, ?, 373
47, 72, 122, ?, 297, 422
What will come in place of the question mark (?) in the following series?
24, 8, 15, ?, 12, 4
12, 18, 30, 54, ?, 198
What will come in place of the question mark (?) in the following series?
9, 22, 61, ?, 217, 334
4, 7, 12, 21, 36, ?