The value of x which satisfies the equation (x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) / (a+b) = 0 is
For this Question put a = 2, b = 1, c = 1 As we Know Here is only one equation and four variable a, b, c & x, so we can put a, b, c anything else we put a = 2, b = 1, c = 1 On putting ((x+4+2 ) / 2) + ((x+1+8) / 3) + ((x+1+2) / 3) = 0 ⇒ ((6+x)/2) + ((9+x)/3) + ((3+x)/3) = 0 ⇒ 18+3x +18+2x+6 + 2x = 0 ⇒ 7x + 42 = 0, x = - 6 ⇒ putting in option a = 2, b = 1, c = 1 we get option (2) satisfy So = -(a²+b²+c²) = - (4+1+1) ⇒ - 6
Select the related word/letters/number from the given alternatives.
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Find the missing term in the given series:
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Find the missing number in the givens series.
99, 143, (?) , 255, 288
Select the number from among the given option that can replace the question mark (?) in the following series.
11, 18, 30, 52, 94, ?
Find the missing term in the following series:
43 44 ? 69 185
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Find the next term / numbers in the given series?
54, 46, 40, 36, ?
15 Select the number from among the given options that can replace the question mark (?) in the following series.
24, 48, 51, 204, 209, ?
