Question
How many numbers between 100 and 500 are divisible by
both 4 and 6?Solution
A number divisible by both 4 and 6 must be divisible by LCM(4, 6) = 12. First number divisible by 12 in the range = 108. Last number divisible by 12 in the range = 492. Number of terms = [(492 - 108)/12] + 1 = (384/12) + 1 = 33. Correct Option: b
How many persons sitting between D and C?
Who among the following stands third to the right of H?
Which one of the following combination is false?
If Z is at extreme right end, then how many persons are sitting Z and H?
Which of the following statement is correct?
If O sits third to the right of F then how many persons are sitting between O and J?
Which of the following is true?
How is U related to Q?
What is the position of O with respect to D?
How many seats are between M and S when counted from the left of S?
Relevant for Exams:
