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Start learning 50% faster. Sign in nowA number divisible by both 4 and 6 must be divisible by LCM(4, 6) = 12. First number divisible by 12 in the range = 108. Last number divisible by 12 in the range = 492. Number of terms = [(492 - 108)/12] + 1 = (384/12) + 1 = 33. Correct Option: b
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