Question
If the seven-digit number 52A6B7C is divisible by 33 and
A, B, C are primes then the maximum value of 3A+2B+5C?Solution
Given number- 52A6B7C. Difference between even and odd places numbers sum will be divisible by 11 ,0 or multiple of 11 5+A+B+C – 2+6+7= 11a A+B+C – 10 =11a    maximum or 0 is minimum So 3A+2B+5C = 3×3+2×5+5×2=9+10+10=29
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