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    Question

    If the seven-digit number 52A6B7C is divisible by 33 and

    A, B, C are primes then the maximum value of 3A+2B+5C?
    A 26 Correct Answer Incorrect Answer
    B 24 Correct Answer Incorrect Answer
    C 29 Correct Answer Incorrect Answer
    D 18 Correct Answer Incorrect Answer

    Solution

    Given number- 52A6B7C. Difference between even and odd places numbers┬а sum┬а will be divisible by 11 ,0┬а or multiple of 11┬а 5+A+B+C тАУ 2+6+7=┬а 11a A+B+C тАУ 10 =11a┬а ┬а ┬а ┬аmaximum or 0 is minimum So 3A+2B+5C = 3├Ч3+2├Ч5+5├Ч2=9+10+10=29

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