If the 6-digit number 1344AB is divisible by 3, 7, and 11, then what is the value of A + B?
Number is divisible by 3,7 and 11 is also divisible by 231. Let the number be 134499. 134499 = 582 × 231 + 57 Required number = 134499 – 57 = 134442 A = 4 and B = 2 A + B = 4+2=6
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