Question
Study the given graph and answer the question that
follows. Break up for distribution (degree wise) of the employees working in five departments (A, B, C, D and E) in a company. Total number of employees = 3000 If 20% of the employees working in department E are transferred to department A, then the difference between the number of employees in A and 124% of the employees working in department C is:Solution
Total number of employees = 3000 Employees in department E = 93° ⇒ Employees in department E = (93°/360°) × 3000 = 775 20% of Employees of department E = (20/100) × 775 ⇒ 20% of Employees of department E = 155 Employees in department A = 64.2° ⇒ Employees in department A = (64.2°/360°) × 3000 = 535 Now, 20% of the employees working in department E are transferred to department A ⇒ Employees in department A = 535 + 155 = 690 ----(1) Employees in department C = 72° ⇒ Employees in department E = (72°/360°) × 3000 = 600 124% of Employees in department C = (124/100) × 600 = 744 ----(2) Required difference = (2) – (1) ⇒ Required difference = 744 – 690 = 54
Identify the wrong sequence
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