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ATQ, we can say that Let 2 days work = 2 × 30 + 40 + 35 = 135 unit 12 days work = 12/2 × 135 = 810 unit Number of days will be minimum when person of higher efficiency work on last day with C, Hence remaining (840 – 810 = 30 unit) work complete by C & A in = 30/(30 + 40) = 3/7 days Total work complete in = (87/7) days
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