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Given that: 4I = IV, 3II = III and 2I = II On solving all three in terms of I :- Ratio of Prices are of I:II:III:IV = 1:2:6:4(given) Price of one vehicle of type ll = 2x= 50,000 x= 25,000 Price of a type I vehicle = 1 × 25,000 = 25,000 Price of a type III vehicle = 6 × 25,000 = 1,50,000 Price of a type IV vehicle = 4 × 25,000 = 1,00,000 Total amount of purchase = 2 × 25,000 + 2 × 50,000 + 2 × 1,50,000 + 2 × 1,00,000 = 50,000 + 1,00,000 + 3,00,000 + 2,00,000 = 6.5 lakhs Balance amount to be paid = 6.5 - 2 = 4.50 Lakhs
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y = x
x.append(4)
print(y)