What is the area of the circular field?
Statement I: The area of the largest square that can be inscribed in the given circular field is 6400 sq. cm.
Statement II : The area of the smallest square in which the given circular field can be inscribed is 4900 sq. cm.
From statement I: Diagonal of the square = Diameter of the circular field Side of square = √6400 cm = 80 cm diagonal of square = √2 side = √2 × 80 = 80√2 cm So 80√2 = 2r So r = 80/√2 Hence Area of the circular field = πr2 = π×(80/√2)^2 = π×6400/2= 3200π cm2 From statement II: Side of a square = √4900 = 70 cm = diameter of circle So 2r = 70 or r = 35cm Area of circular field = πr2 = π×352 = 1225π cm2 So answer can be determined by either of statement I or II.
32 of (16/8) of (30/24) of (120/x) = 30
22% of 280 + 34% of 1080 × 5/12 =? + 16% of 460
2.4 of 7.2 of 1/57.6 of 4200 = ?
44% of 1250 + 46 × 34 = 40% of ? + 1154
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
1(1/2)+ 11(1/3) + 111(1/2) + 1111(1/3) + 11111(1/2) = ?
(630 ÷ 35) × 2 + 144 = ? × 2
(√2704 x 55)/(245 + 120) =?
33 × 5 - ?% of 250 = 62 - 6