Question
A car travels from village A to village B at a speed 20% faster than its usual speed and arrives 30 minutes early. If the distance between A and B is 165 km, determine the carβs usual speed.
Solution
Let the usual speed of car = 10x km/h Speed of car when it travels with 20% more speed = 120% of 10x = 12x Difference of time taken = 30 minutes 165/10x β 165/12x = 30/60 x = 5.5 usual speed of car = 10x = 55 km/h
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