Question
Two mixtures A and B are in the ratio of 3:2. Mixture A
contains ×% of milk and a% of water. Mixture B contains y% of milk and b% of water. If mixture B is mixed with mixture A then the final quantity of milk becomes 23% of the total mixture. Find the quantity of final milk, if x + y =45. i. x - y = 10 ii. If the initial quantity of mixture A is 60 liter out of which 15 liter is milk. iii. If 15 liter mixture is taken out from mixture A and mixed with mixture B the total quantity of water in mixture B becomes is 40 liter.Solution
Let mixture in A and B be 3h and 2h respectively. Quantity of milk = (3hx/100 + 2hy/100)/5h = 23/100 3x + 2y = 115------(1) Given that, x + y = 45-----(2) y = 45 – x putting the value of y in equation 1 3x + 2(45 – x) = 115 3x + 90 – 2x = 115 x = 25 y = 20 Now from statement i: We cannot find the quantity of final milk. From Statement ii: 3h = 60 h = 20 therefore, we can find the quantity of final milk from statement ii. So, only statement ii is required for giving the answer.
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...