Question
Jolly borrowed some money at compound interest for 4
years. What will be the amount required to return after 4 years? Statement I: If the amount was borrowed at simple interest, then after 10 years Rs 1200 was required to pay as simple interest. Statement II: The rate of interest is 12% per annum Statement III: The sum of money borrowed is 15 times the amount required to be paid as simple interest after 3 years. In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly which statement/s are sufficient to find the answer .Solution
From I: SI after 10 years is Rs 1200, so after 1 year = 1200/10 = Rs 120 so,SI of 1 year = Rs. 120 From III: Principal = 15 × S.I after 3 years or P = 15 × P× R ×3/100 or R = 100/45% So from I and II, SI =120 = P× R×1/100 = P × (100/45) /100 So we can find Principal. then we can find the required amount by CI formula So from I and II, SI =120 = P× R×1/100 = P × (12) /100 So we can find Principal, then we can find the required amount by CI formula
Statements: A @ Z, Z # L, L % N, N @ U
Conclusions:
I. A @ N
II. Z @ U
III. A # L
Statements: A ≤ J ≤ K = M; Y ≥ Z > A
Conclusions:
I. J ≤ Z
II. Z ˃ Y
Statement: K = B; D ≥ L ≥ T ≥ B
Conclusion: I. D > K II. D = K
Statements: U > H ≥ W; S > T ≥ B; S < H; C ≤ D = U
Conclusions:
I. D > B
II. T < U
III. W ≤ D
Statements:
E ≥ H > O < R > U = X
Conclusions:
I. E < O
II. X = O
In the question, assuming the given statements to be true, Find which of the conclusion (s) among given three conclusions is /are definitely true and t...
In this question, the relation between various elements is shown in the statement. After the statement, two conclusions are given, select a suitable op...
Statements: A % B & G @ T $ D; W % A # P
Conclusions :Â Â Â Â Â I. D % BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. A % GÂ Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: V > R ≥ W < Z; X ≤ W; U < R ≤ Y
Conclusions:
I. X < Z
II. W < Y
III. Z > UÂ
Statements: A ≥ B ≥ C = M = N ≥ O ≤ P ≤ Y = Z
Conclusions:
I. Y > M
II. Z ≤ A