Question
What is the value of (4ab+ab2)/(a2
b),  a,b ≠0 I. a + b = 0 II. a – b = 1 Each of the following questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give the answer.Solution
(4ab+ab2)/(a2 b)=  (4+b)/a From I, we get a = -b And from II, we get a = 1 + b Putting the values of ‘a’ in the above equation and equating both (4+b)/a = (4+b)/(-b) Also, (4+b)/a=  (4+b)/(1+b) = (4+b)/(-b) b = -1/2 a = 1/2 (4ab+ab2)/(a2 b)=  (4(-1/4)+1/2 x (-1/2)2)/((1/2)2 (-1/2))=  (-1+1/8)/(-1/8)=7
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