What is the value of (4ab+ab^{2})/(a^{2} b), a,b ≠0

I. a + b = 0

II. a – b = 1

(4ab+ab^{2})/(a^{2} b)= (4+b)/a From I, we get a = -b And from II, we get a = 1 + b Putting the values of ‘a’ in the above equation and equating both (4+b)/a = (4+b)/(-b) Also, (4+b)/a= (4+b)/(1+b) = (4+b)/(-b) b = -1/2 a = 1/2 (4ab+ab^{2})/(a^{2} b)= (4(-1/4)+1/2 x (-1/2)^{2})/((1/2)^{2} (-1/2))= (-1+1/8)/(-1/8)=7

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