Question
If points A(–2, 3) and B(4, –3) are ends of a
diameter, find equation of the circle.Solution
ATQ,
Center = ((–2+4)/2, (3–3)/2) = (1, 0), radius = √[(4–1)² + (–3–0)²] = √(9+9)=√18=3√2 Equation: (x–1)² + y² = 18.
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