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For finding the perpendicular distance between two lines ax + by = C1, ax + by = C2 Coefficients must be equal then Perpendicular Distance = |C1-C2|/√(a2+ b2) 6x + 8y = 18 …………(i) 12x + 16y =20…………..(ii) Multiplying equation (i) with 2 12x + 16y =36 Now the Perpendicular Distance = |36-20|/√(12² + 16²) = 16/20 = 0.8
24.99% of 1619.78 + (1259.84 ÷ 12.24) = ? × 16.98
What will be the approximate value of the following questions.
(89.90% of 479.88 - 2/5 of 400.11)² ÷ (50.11% of 359.77 + √224.85) = ?
A regular hexagon has a side length of 8 units. What is the area of the half of the hexagon?
139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98
15.232 + 39.98% of 539.99 = ? × 6.99
(124.99)² = ?
√1567.763`xx` √4400 ÷ 326.9827 + 1223.293 = ?
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
228.45 + 19.06² + ?³ = √1024.97 * 33.12