Question
Find the compound interest on Rs 10,000 at 8% per annum,
compounded half-yearly, for 1.5 years.Solution
Rate per half-year = 8%/2 = 4% Number of half-years in 1.5 years = 3 Amount A = P(1 + r/100)^n = 10000 × (1.04)^3 Compute (1.04)^2 = 1.0816 Then (1.04)^3 = 1.0816 × 1.04 = 1.124864 So A ≈ 10000 × 1.124864 = Rs 11,248.64 Compound Interest = A − P = 11,248.64 − 10,000 = Rs 1,248.64.
What will come in the place of question mark (?) in the given expression?
(30 × 5 + 20) × 2 = ?
What will come in the place of question mark (?) in the given expression?
24% of 350 + 246 = ? + 50 × 2.5
Find the value of the given expression.
[76 – {90 ÷ 5 × (24 – 36 ÷ 3) ÷ 3}]
Simplify the following expression:
(168 ÷ 12 + 19 × 64)/(22+1) = ?
The valueof2 of5– 1/2 −[4÷2– 1/3 −{3/4−(5– 1/2 – 3/4 )}]is :
1123 + 1452 + 1015 - 2640 = ?
- Simplify:
25% of 1000 + 10% of 150 – 22 × ? = 45
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