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Let the rate of C.I be R percent per annum, CI = P [ ( 1 + `(R)/(100)` )ᵀ - 1] ⇒ 6,120 = 75,000 [ ( 1 + `(R)/(400)` )2 - 1 ] [T= 6 months = 2 because interest is calculated quarterly] ⇒ `(6120)/(75000)` = ( 1 +`(R)/(400)` ) 2 - 1 ⇒ ( 1 + ) 2 - 1 = `(51)/(625)` ` ` ⇒ ( 1 + `(R)/(400)` ) 2 = 1 +`(51)/(625)` ⇒ ( 1 + `(R)/(400)` )2 =`(676)/(625)` ⇒ ( 1 +`(R)/(400)` )2 = ( `(26)/(25)` )2 ⇒ 1+ `(R)/(400)` =`(26)/(25)` ⇒ `(R)/(400)` = `(26)/(25)` - 1 =`(1)/(25)` R = `(400)/(25)` = 16% Now, S.I = `(P xx R xx T)/(100)` = `(75000 xx 16 xx 18)/(100 xx 12)` = Rs. 18,000
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?
(3/7) x 868 + 25% of 240 = (? + 65)
[{(1296 ÷ 18) ÷ 12} ÷ 6] + 82 + √625 = ?
∛857375 + ∛91125 = ? + √6889
5.5 × 3.2 × 2.3 = ?
(92.03 + 117.98) ÷ 14.211 = 89.9 – 30.23% of ?
Evaluate: {2 x (0.718 + 0.982) + 0.008 of 5000}