Question
In a circle of radius 10 cm, a chord is at a distance 6
cm from the centre. The length of the chord is:Solution
Perpendicular from centre to chord bisects the chord. Let half of the chord = x Then, x^2 + 6^2 = 10^2 x^2 + 36 = 100 x^2 = 64 x = 8 Chord length = 2x = 16 cm
The simple interest on a sum of Rs 5000 at 8% per annum for 3 years is:
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