Question
A square ABCD is inscribed in a quadrant APCQ in the
given figure. If AB = 20 cm, find the area of the shaded region (take π=3.14) correct to two places of decimalSolution
Side of square = 20 Radius of quadrant =Diagonal of square R= 20√2 Area of the shaded region = area of quadrant – area of square = πr²/4 - side² = (3.14×20√2×20√2)/4 - 400 =400(3.14 – 2)/2 =200×1.14 =228cm²
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