Question
Find the average of the initial quantity of vessel A
and initial quantity of vessel B. Study the data carefully and answer the following questions: There are three types of mixtures in three different vessels A, B and C. The ratio of milk and water in vessel A is 5:2. The ratio of milk and P1 in vessel B is 2:1. The quantity of water in vessel C was equal to that of vessel A. If 28 litres of mixture from vessel A is taken out and poured in vessel B, then the quantity of milk in vessel B becomes 40 litres. If 40% of the mixture from vessel C is taken out then the quantity of P1 in vessel C becomes 15 litres. Ratio of quantities of mixture in B and C is 6:13. Note: P1 is soluble component. Vessel A, B and C do not contain P1, water and milk respectively.Solution
Milk Water P1 A 5x 2x - B 2y - y C - 2x Vessel A, => 5x + 2x = 28 => x = 4 Quantity of milk in vessel A = 5x = 20 Quantity of water in vessel A = 2x = 8 Quantity of milk in vessel B, => 2y + 20 = 40 => y = 10 litres Quantity of milk in vessel B = 20 litres Quantity of P1 in vessel C = (1500/60) = 25 litres Now, ratio of quantities of mixture in B and C is 6:13. => 30/C = 6/13 => C = 65 Quantity of mixture in C = 65 litres So, 2x + 25 = 65 => 2x = 40 litres Quantity of milk in vessel A = 40 litres Quantity of water in vessel A = 100 litres Required average = (20 + 10 + 100 + 40)/2 = 85
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ? What will come in the place of question mark (?) in the given expression?
√144 X √324 + ? = 83 + 31 X √16

The value of 11 × 11 + 11 ÷ 11 – 11 × 11 + 11 + 11 × 11 – 11 – 11 × 11 is:
√ 225 x 24 - √ 144 x 18 = ?
(64/25)? × (125/512)?-1 = 5/8
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
40 of 30% of 220 = ? + 790
[(4/3) + (5/6)] of 378 = ?
