Question
Find the average of the initial quantity of vessel A
and initial quantity of vessel B. Study the data carefully and answer the following questions: There are three types of mixtures in three different vessels A, B and C. The ratio of milk and water in vessel A is 5:2. The ratio of milk and P1 in vessel B is 2:1. The quantity of water in vessel C was equal to that of vessel A. If 28 litres of mixture from vessel A is taken out and poured in vessel B, then the quantity of milk in vessel B becomes 40 litres. If 40% of the mixture from vessel C is taken out then the quantity of P1 in vessel C becomes 15 litres. Ratio of quantities of mixture in B and C is 6:13. Note: P1 is soluble component. Vessel A, B and C do not contain P1, water and milk respectively.Solution
         Milk      Water      P1 A        5x           2x            - B        2y             -            y              C          -             2x Vessel A, => 5x + 2x = 28 => x = 4 Quantity of milk in vessel A = 5x = 20 Quantity of water in vessel A = 2x = 8 Quantity of milk in vessel B, => 2y + 20 = 40 => y = 10 litres Quantity of milk in vessel B = 20 litres Quantity of P1 in vessel C = (1500/60) = 25 litres Now, ratio of quantities of mixture in B and C is 6:13. => 30/C = 6/13 => C = 65 Quantity of mixture in C = 65 litres So, 2x + 25 = 65 => 2x = 40 litres Quantity of milk in vessel A = 40 litres Quantity of water in vessel A = 100 litres 
Required average = (20 + 10 + 100 + 40)/2 = 85
50 ÷ 2.5 × 64 + ? = 1520
(25 × 12 + 30 × 8 – 22 × 10) = ?
4261 + 8234 + 2913 + 8217 + 6283 + 4172 =?
7292/3 = ?
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 √9604 + ∛205379 + 58% of 1500 = 520 + ?
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
If x - 1/x = 9, then the value of x² + 1/ x² is:
What will come in place of the question mark (?) in the following expression?
46 – 5² + 8² + 3² = ? × 4
What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?
