Question
The greater of the two numbers whose product is 900 and
sum exceeds their difference by 30 isSolution
Let's consider two numbers as x & y. Given that, Product of two numbers x & y is xy=900 ---- (1) and sum of the two numbers exceeds the difference by 30 i.e.., (x + y) − (x − y) = 30 => 2y=30 => y=15 Substituting y=15 in equation 1, we get x=60
25Â Â Â Â Â Â Â Â Â Â 34Â Â Â Â Â Â Â Â Â Â 61Â Â Â Â Â Â Â Â Â Â 106Â Â Â Â Â Â Â Â 169Â Â Â Â Â Â Â Â ?
...5, 11, 19, 29, 41, ?
30, 39, 66, ? , 174, 255
11Â Â 34Â Â 135Â Â 676Â Â 4055Â Â Â ?
412, 537, 573, 916, 980, ?
3 ? 7 16 71 346
...If the first term of the arithmetic progression is 18, the common difference is 5, and the number of terms in the series are 40, then find the sum of th...
35, 36, 40, 49 , 65 , ?
33Â Â Â 68Â Â Â 103Â Â Â 138Â Â Â 173Â Â Â ?
124    174    211    ?     254    264
...
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