Let x is the maximum marks of the examination. Given that Megha failed by 6 marks ⇒ Minimum Pass Mark = 38x/100 + 6......(Equation 1) Given that Teena got 14 marks more than the passing marks ⇒Minimum Pass Mark =42x/100 −14......(Equation 2) From equations 1 and 2, we have => 38x/100 + 6 = 42x/100 − 14 ⇒4x/100 = 20 ⇒ x = 100 × 20/4 = 500 ⇒ Maximum marks of the examination = x = 500 Minimum Pass Mark = 38 × 500/100 + 6 = 190 + 6 = 196
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