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    Question

    If a boat's downstream and upstream speeds are 30 km/hr

    and 22 km/hr respectively, and it travels (x + y) km upstream in 10 hours when the stream speed is twice the regular one, what is the average of x and y?
    A 90 km Correct Answer Incorrect Answer
    B 60 km Correct Answer Incorrect Answer
    C 73 km Correct Answer Incorrect Answer
    D 85 km Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let, speed of boat in still water and stream speed be B km/hour and s km/hour, respectively.

    So, (B + s) = 30 … (i)

    Also, (B – s) = 22 … (ii)

    Solving equation (i), and (ii), we get,

    B = 26 km/hour

    s = 4 km/hour

    According to question,

    (x + y)/(B – 2s) = 10

    (x + y) = 10 × (26 – 2 × 4) = 10 × 18 = 180 km

    Therefore, average value of x and y = (x + y)/2 = 180/2 = 90 km

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