Question
A boat covers a certain distance against the stream in 9
hours 36 min and it covers the same distance along the stream in 6 hours. What is the ratio of the speed of the boat in still water to that of the stream?Solution
Let the speed of boat in still water =B and speed of stream =S then Speed of boat in Downstream =B+S, and Time = 6h Speed of boat in Upstream=B-S, Time = 9 h 36min=96/10=48/5h ATQ- 48/5(B-S) =6(B+S) 
B-S=10            … (1) B+S=16          … (2) B=13, S=3 Now ratio of boat speed and stream speed = 13:3
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
- If the quadratic equation x² + 18x + n = 0 has real and equal roots, what is the value of n?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 27x² - 114x + 99 = 0
Equation 2: 18y² - 70y + 68 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 8x – 3y = 85
II. 4x – 5y = 67
I. 6x2 - 41x+13=0
II. 2y2 - 19y+42=0
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