Question
Speed of current is equal to 15% of speed of boat in
still water. If the boat takes 3 hours to cover 120 km in still water, then find the time taken by the boat to cover 68 km in upstream.Solution
Speed of the boat in still water = 120 ÷ 3 = 40 km/h Speed of current = 40 × 0.15 = 6 km/h Therefore, upstream speed of the boat = 40 – 6 = 34 km/hr Required time taken = 68 ÷ 34 = 2 hours
I. y/16 = 4/yÂ
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
The roots of x² − (k+3)x + (3k − 1) = 0 are real and distinct, and the larger root exceeds the smaller by 5. Find k.
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 2x² - 8x + 6 = 0
Equation 2: y² - 7y + 10 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
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