Question
Boat ‘A’ can cover 150 km in still water in 15
hours. In still water, if the ratio of the speed of boat ‘A’ to that of ‘B’ is 5:1 and the speed of stream is 3 km/hr then find the time taken by boat ‘B’ to cover the 60 km in downstream.Solution
Speed of boat ‘A’ in still water = 150/15 = 10 km/hr Speed of boat ‘B’ in still water = 10 × (1/5) = 2 km/hr Downstream speed of boat ‘B’ = 2 + 3 = 5 km/hr Time taken by boat ‘B’ to cover 60 km in downstream = 60/5 = 12 hours
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
[(4/3) + (5/6)] of 378 = ?
What will come in the place of question mark (?) in the given expression?
48 ÷ 4 × (3 + 5) – 6² + 10 = ?
What value should come in place of the question mark (?) in the following question?
1250 − ( 320 + 180 ) × ...
(360 - ?)/(25% of 96) = 13
What value will come in place of (?) question mark in the given expression.
3³ + 4² × 5 – 28 = ?
What value should come in the place of (?) in the following questions?
53 × 12 + 43 × 13= ? × 7 - 12% of 1300
2*1/3 + 22*1/3 + 222*1/3 + 2222*1/2 + 22222*1/2 = ?
Solve for the ?
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
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