Question
The speed of the stream is 10 km/h. Boat ‘A’ covers
180 km distance against the stream in 6 hours and boat ‘B’ covers 90 km distance against the stream in 2 hours. The speed of boat ‘B’ in still water is how much percent of the speed of boat ‘A’ in still water?Solution
Speed of boat ‘A’ upstream = 180/6 = 30 km/h Speed of boat ‘B’ upstream = 90/2 = 45 km/h Speed of the boat ‘A’ in still water = 30 + 10 = 40 km/h Speed of the boat ‘B’ in still water = 45 + 10 = 55 km/h Required percentage = (55/40) × 100 = 137.5%
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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