Question
A boy can swim a certain distance downstream in 4 hours
and return in 5 hours. If the rate of stream is 3 kmph then what is the speed of boy in still water?Solution
Let the speed of the boy in still water be x kmph. Then, (x + 3) × 4 = (x – 3) × 5 => 4x + 12 = 5x - 15 => x = 27 kmph
36% of 250 + 26 ÷ 2 × ? = 207
What will come in the place of question mark (?) in the given expression?
45% of (√6400 × 5) = ? + 111Â
(72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
[(40)2 ÷ 32 × 4] ÷ 50 = ?
Find the simplified value of the given expression.
{12.75 × √64 + 13.5 × √(√256)} ÷ 6 + 49.5 ÷ 5.5Â
10 × 100 ÷ 5 + 9 = ?
What will come in the place of question mark (?) in the given expression?
40% of 150 - ?% of 75 = 15 × 1.6
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
(3/7) x 868 + 25% of 240 = (? + 65)