Rate downstream = 4/6 x 60 = 40 km/hr Rate upstream = 24/3 = 8 km/hr Speed of current = 1/2 (Rate downstream – Rate upstream) ⇒ 1/2 (40 – 8) km/hr = 16 km/hr
Find the value of sin(θ) if 2sinθ = tanθ, for 0 < θ < 90°.
If cot A = 12/5, then the value of (sin A + cos A) × sec A is ________.
If sin A = (4/5), then find the value of {cosec A × cos A + sec A × tan A}.
If A + B = 450 , then the value of 2(1 + tanA) (1 + tanB) is:
which of the following is equal to [(tan θ +secθ -1)/ (tanθ-secθ +1)]
if a sin 45 ˚ = b cosec 60 ˚ then find the value of a⁴/b⁴
...cos (sec-1 x) is equal to –
The maximum value of 45 sin θ + 28 cos θ is:
