Question
A boat takes 1/3rd time in moving a certain distance
downstream than upstream. The ratio of the speed of the boat in still water and that of current is.Solution
Downstream speed = x+y Upstream speed = x-y Speed = distance/time ∴ x+y = D/T .................... (i) x-y = D/3T .................... (ii) From (i) & (ii) 2x = D/T + D/3T 2x = (3D+D)/3T = 4D/3T x = 2D/3T and; y = D/T - 2D/3T = D/3T x/y = 2D/3T × 3T/D x/y = 2
More Boats and streams Questions
464 + 181 +? = (154 × 25) - (15) 2 Â
(62 + 82 ) X ? = 80% of 500 - 25 X 4
? = 2640 ÷ {(35% of 1240) – 170}Â
2*1/3 + 22*1/3 + 222*1/3 + 2222*1/2 + 22222*1/2 = ?
154 × 7 + 480 × 5 = ?% of 6956
120% of 25 + 80 X 2 = ?2 - 6
√1444 + √729 – √2116 = ?
30 of 20 - 40 + 182 - 23 × ? = 83Â
10% of 100 + 14 = ?% of 120
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