Question
The average of 12 consecutive even numbers  is 41 . If the smallest 5 numbers  are removed, what is the average of the remaining numbers?
Solution
12 consecutive even numbers with average 41 are: 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52 Remove the smallest 5 numbers: 40, 42, 44, 46, 48, 50, 52 Sum = 40 + 42 + 44 + 46 + 48 + 50 + 52 = 322 Average = 322 / 7 = 46
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