Question
The average of 5 numbers is 46. If one number, 38, is
removed, what is the average of the remaining 4 numbers?Solution
ATQ, Total of 5 numbers = 46 * 5 = 230 Sum of remaining 4 = 230 - 38 = 192 New average = 192 / 4 = 48
Find the value of 'a' in the given data if the mean of the given data is 16.
10, 12, 18, 20, 15, 17, a, 14, 13, 19
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The sum of the digits of a two-digit number is 12, and the tens digit is twice the units digit. Determine the HCF of this number ...
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