Question
The average of series 'S8', which consists of 6 consecutive
even numbers, is 35. The second term of series 'T8', which consists of 5 consecutive odd numbers, is 5 more than the first term of series 'S8'. Find the average of series 'T8'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 35 X 6
Or, 6a = 210 - 30
So, 'a' = (180 / 6) = 30
So, 2nd term of series 'T8' = 30 + 5 = 35
So, series 'T8' = 33, 35, 37, 39, 41
Therefore, required average = (33 + 35 + 37 + 39 + 41) Ă· 5 = 37
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