Question
The average of series 'S3', which consists of 6 consecutive
even numbers, is 33. The second term of series 'T3', which consists of 5 consecutive odd numbers, is 5 more than the first term of series 'S3'. Find the average of series 'T3'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 33 X 6
Or, 6a = 198 - 30
So, 'a' = (168 / 6) = 28
So, 2nd term of series 'T3' = 28 + 5 = 33
So, series 'T3' = 31, 33, 35, 37, 39
Therefore, required average = (31 + 33 + 35 + 37 + 39) ÷ 5 = 35
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