Question
The average of series 'S5', which consists of 6
consecutive even numbers, is 23. The second term of series 'T5', which consists of 5 consecutive odd numbers, is 5 more than the first term of series 'S5'. Find the average of series 'T5'.Solution
Let six consecutive even numbers be 'a', (a + 2), (a + 4), (a + 6), (a + 8) and (a + 10), respectively.
ATQ,
a + a + 2 + a + 4 + a + 6 + a + 8 + a + 10 = 23 X 6
Or, 6a = 138 - 30
So, 'a' = (108 / 6) = 18
So, 2nd term of series 'T5' = 18 + 5 = 23
So, series 'T5' = 21, 23, 25, 27, 29
Therefore, required average = (21 + 23 + 25 + 27 + 29) ÷ 5 = 25
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