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    Question

    The average of two numbers β€˜K’ and β€˜L’ is 480

    such that they are in the ratio 3:5 respectively. Another number β€˜M’ is 120 more than β€˜L’ and fourth number β€˜N’ is 25% of the β€˜K’. Find the average of β€˜M’ and β€˜N’.
    A 395 Correct Answer Incorrect Answer
    B 400 Correct Answer Incorrect Answer
    C 405 Correct Answer Incorrect Answer
    D 410 Correct Answer Incorrect Answer

    Solution

    Sum of β€˜K’ and β€˜L’ = 480 Γ— 2 = 960
    Therefore,
    β€˜K’ = 960 Γ— (3/8) = 360
    β€˜L’ = 960 – 360 = 600
    β€˜M’ = 600 + 120 = 720
    β€˜N’ = 0.25 Γ— 360 = 90
    Required average = {(720 + 90)/2} = 405

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