Question
The average of two numbers βKβ and βLβ is 480
such that they are in the ratio 3:5 respectively. Another number βMβ is 120 more than βLβ and fourth number βNβ is 25% of the βKβ. Find the average of βMβ and βNβ.Solution
Sum of βKβ and βLβ = 480 Γ 2 = 960
Therefore,
βKβ = 960 Γ (3/8) = 360
βLβ = 960 β 360 = 600
βMβ = 600 + 120 = 720
βNβ = 0.25 Γ 360 = 90
Required average = {(720 + 90)/2} = 405
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