Question
The average of two numbers ‘K’ and ‘L’ is 480
such that they are in the ratio 3:5 respectively. Another number ‘M’ is 120 more than ‘L’ and fourth number ‘N’ is 25% of the ‘K’. Find the average of ‘M’ and ‘N’.Solution
Sum of ‘K’ and ‘L’ = 480 × 2 = 960
Therefore,
‘K’ = 960 × (3/8) = 360
‘L’ = 960 – 360 = 600
‘M’ = 600 + 120 = 720
‘N’ = 0.25 × 360 = 90
Required average = {(720 + 90)/2} = 405
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