Question
The average of two numbers ‘U’ and ‘V’ is 420 such
that they are in the ratio 4:2 respectively. Another number ‘W’ is 180 more than ‘V’ and fourth number ‘T’ is 75% of the ‘U’. Find the average of ‘W’ and ‘T’.Solution
Sum of ‘U’ and ‘V’ = 420 × 2 = 840
Therefore,
‘U’ = 840 × (4/6) = 560
‘V’ = 840 – 560 = 280
‘W’ = 280 + 180 = 460
‘T’ = 0.75 × 560 = 420
Required average = {(460 + 420)/2} = 440
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