Question
The average of two numbers βXβ and βYβ is 400
such that they are in the ratio 3:5 respectively. Another number βZβ is 80 more than βYβ and fourth number βWβ is 10% of the βXβ. Find the average of βZβ and βWβ.Solution
Sum of βXβ and βYβ = 400 Γ 2 = 800
Therefore,
βXβ = 800 Γ (3/8) = 300
βYβ = 800 β 300 = 500
βZβ = 500 + 80 = 580
βWβ = 0.1 Γ 300 = 30
Required average = {(580 + 30)/2} = 305
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