Question
The average of two numbers ‘X’ and ‘Y’ is 400
such that they are in the ratio 3:5 respectively. Another number ‘Z’ is 80 more than ‘Y’ and fourth number ‘W’ is 10% of the ‘X’. Find the average of ‘Z’ and ‘W’.Solution
Sum of ‘X’ and ‘Y’ = 400 × 2 = 800
Therefore,
‘X’ = 800 × (3/8) = 300
‘Y’ = 800 – 300 = 500
‘Z’ = 500 + 80 = 580
‘W’ = 0.1 × 300 = 30
Required average = {(580 + 30)/2} = 305
More Average Questions
The minimum value of 45 sin2 θ + 28 cos2 θ is
Evaluate the following:
sin 60° × cos 30° + sin 30° × cos 60°
If 4sin² θ = 3(1+ cos θ), 0° < θ < 90°, then what is the value of (2tan θ + 4sinθ - secθ)?
- If 2cos²A + 3sin²A = 13/5, then find the value of (sec²A - 1)
- If sin (a + b) = (√3/2) and cos (a – b) = (√3/2), then find sin a.
sin2 17˚ + sin2 19˚ + sin2 21˚ + sin2 23˚ + ……… + sin2 77˚ = ?
If tan² 45°- cos² 60° x sin 45° cos 45° cot 30°, then find the value of 'x'.
If SecA + TanA = 2√2 + 9, then find the value of Sin A + Cos A.
Relevant for Exams:
