Question
The average of two numbers βPβ and βQβ is 480
such that they are in the ratio 5:7 respectively. Another number βRβ is 60 more than βQβ and fourth number βSβ is 50% of the βPβ. Find the average of βRβ and βSβ.Solution
Sum of βPβ and βQβ = 480 Γ 2 = 960
Therefore,
βPβ = 960 Γ (5/12) = 400
βQβ = 960 β 400 = 560
βRβ = 560 + 60 = 620
βSβ = 0.5 Γ 400 = 200
Required average = {(620 + 200)/2} = 410
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