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    Question

    Average of five consecutive numbers is 48. Find the sum

    of smallest and largest number.
    A 92 Correct Answer Incorrect Answer
    B 94 Correct Answer Incorrect Answer
    C 96 Correct Answer Incorrect Answer
    D 98 Correct Answer Incorrect Answer

    Solution

    Let the numbers be (a - 2), (a - 1), a, (a + 1) and (a + 2).
    So, (a - 2 + a - 1 + a + a + 1 + a + 2) ÷ 5 = 48
    Or, (5a/5) = 48
    Or, 'a' = 48
    Required sum = a - 2 + a + 2 = 2a = 2 × 48 = 96

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