Question
What is the average of the squares of the first 41
natural numbers?Solution
Sum of squares of first 'n' natural numbers = n × (n + 1) × (2n + 1) ÷ 6
So, average = n × (n + 1) × (2n + 1) ÷ 6n = (n + 1) × (2n + 1) ÷ 6
= (41 + 1) × (2 × 41 + 1) ÷ 6
= 42 × 83 ÷ 6
= 581
More Average Questions
What is (0.08% of 0.008% of 8)1/9 ?
72 x 60 x 22 x 32 =?
641.5 + 72 × 8 = ? × 4
? = 6.25% of 240 + 252 + 172 – 16 × 17
∛21952 × 44 = ? × 14
(33 + 6.25% of 4096) = ? + 2 × 119
- What will come in the place of question mark (?) in the given expression?
62.5% of 120 + ? = (720 + 90) ÷ √36 Simplify the expression and find the value of 'x'
35% of 500 of 18 ÷ 21 = x
What will come in the place of question mark (?) in the given expression?
24% of 350 + 246 = ? + 50 × 2.5
(23 × 8) – (13 × 5) + 67 =? x 6         Â
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