Question
Find the sum of the first and last numbers if the
average of seven continuous numbers is 90.Solution
ATQ,
Let numbers be: (a - 3), (a - 2), (a - 1), a, (a + 1), (a + 2), (a + 3)
Sum = (7a) and average = (7a / 7) = 90
⇒ a = 90
Sum of smallest and largest = (a - 3) + (a + 3) = 2a = 2 × 90 = 180
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