Question
The average of the present age of 'D' and 'E' is 40 years. If the ratio of the age of 'D' 5 years ago to the age of 'E' 5 years hence is 2:3, then find the age of 'E' 10 years hence from now.
Solution
ATQ,
Let the age of 'D' 5 years ago be 2x years.
Let the age of 'E' 5 years hence be 3x years.
So, the present age of 'D' = 2x + 5
So, the present age of 'E' = 3x - 5
Sum = 40 × 2 = 80
2x + 5 + 3x - 5 = 80
5x = 80
x = 16
Present age of 'E' = 3x - 5 = 48 - 5 = 43
Age of 'E' 10 years hence = 43 + 10 = 53 years
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