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    Question

    The average of the present age of 'D' and 'E' is 40

    years. If the ratio of the age of 'D' 5 years ago to the age of 'E' 5 years hence is 2:3, then find the age of 'E' 10 years hence from now.
    A 35 yrs Correct Answer Incorrect Answer
    B 42 yrs Correct Answer Incorrect Answer
    C 79 yrs Correct Answer Incorrect Answer
    D 53 yrs Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the age of 'D' 5 years ago be 2x years.

    Let the age of 'E' 5 years hence be 3x years.

    So, the present age of 'D' = 2x + 5

    So, the present age of 'E' = 3x - 5

    Sum = 40 × 2 = 80

    2x + 5 + 3x - 5 = 80

    5x = 80

    x = 16

    Present age of 'E' = 3x - 5 = 48 - 5 = 43

    Age of 'E' 10 years hence = 43 + 10 = 53 years

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