Question
There are three distinct numbers βmβ, βnβ and
βoβ. If, m = 210, (m + n) = 510 and (o β n) = 60, then find the average of m, n and o.Solution
Given, m = 210, (m + n) = 510 and (o β n) = 60 Therefore, n = 510 β 210 = 300 And, o = 300 + 60 = 360 Required average = (210 + 300 + 360)/3 = 870/3 = 290
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